The International Space Station orbital speed
The International Space Station orbital speed Let's determine the orbital speed and period for the International Space Station (ISS): ISS orbits about 400 km above the Earth's surface, which means that radius of its orbit is R_E (Earth's radius) + 400 km. It is easier to determine orbital speed and orbital period of satellite for circular orbits. We have satellite of mass m in a circular orbit about Earth at distance r from center of the Earth. It has centripetal acceleration directed toward the center of the Earth. Earth's gravity is the only force acting, so Newton's second law gives Gm M E r 2 = m a c = m v 2 orbit r . Which re-arrange into v_orbit = (G M E / r)^1/2 To find the period of a circular orbit, we note that the satellite travels the circumference of the orbit 2πr in one period T. Using the definition of speed, we have v_orbit=2πr/T, which gives T = 2πr/v_orbit. Let's calculate orbit speed for ISS. so, the orbital speed is 767 m/s (compa...